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John is putting a fence around his garden that is shaped like a half circle and a rectangle.

A rectangle has a length of 14 feet and width of 7 feet. A semicircle with diameter of 7 feet is on top of the rectangle.

How much fencing will John need? Use StartFraction 22 over 7 EndFraction for Pi.
A.32 ft
B.39 ft
C.46 ft
D.57 ft

Respuesta :

calculista

Answer:

C.46 ft

Step-by-step explanation:

we know that

The perimeter of the garden is equal to sum three sides of the rectangle plus the circumference of a semicircle

so

[tex]P=2L+W+\frac{1}{2}\pi D[/tex]

we have

[tex]L=14\ ft\\W=7\ ft\\D=7\ ft\\\pi =\frac{22}{7}[/tex]

substitute the given values

[tex]P=2(14)+7+\frac{1}{2}(\frac{22}{7})(7)[/tex]

[tex]P=28+7+11=46\ ft[/tex]

reet9352

Answer:

46

Step-by-step explanation:

took it on edge bro

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