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At a certain temperature the rate of this reaction is first order in SO₃ with a rate constant of 0.208 s⁻¹:
2SO₃(g) → 2SO₂(g) + O₂(g)

Suppose a vessel contains SO₃ at a concentration of 1.36M.
Calculate the concentration of SO₃ in the vessel 7.30 seconds later. You may assume no other reaction is important. Round your answer to 2 significant digits.

Respuesta :

Answer:

0.30 M

Explanation:

Using integrated rate law for first order kinetics as:

[tex][A_t]=[A_0]e^{-kt}[/tex]

Where,  

[tex][A_t][/tex] is the concentration at time t  = ?

[tex][A_0][/tex] is the initial concentration  = 1.36 M

k is the rate constant = 0.208 s⁻¹

t = 7.30 seconds

So,  

[tex][A_t]=1.36\times e^{-0.208\times 7.30}\ M=0.30\ M[/tex]

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