Answer:
Step-by-step explanation:
Given that the volume V of a right circular cylinder of radius r and height h is [tex]V=\pi r^2h[/tex]
To find rate of change of V with respect to rate of change of radius
Here given that h is constant
So differentiation with respect to t gives
[tex]\frac{dv}{dt} =2\pi r h \frac{dr}{dt}[/tex]
This would be dv/dt i.e. rate of change of volume with respect to time in terms of dr/dt
This varies whenever r varies
