Answer:
(1.5,-2.6)
Step-by-step explanation:
Given the polar coordinates (-3,60°).
Let our Cartesian coordinates be (x,y)
#We know that when converting the rectangular coordinates (x,y) to polar (r,θ), then:
[tex]r=\sqrt{x^2+y^2}\\\\\therefore r^2=x^2+y^2\\\\\theta=tan^{-1}(y/x)\\\therefore tan \theta=y/x[/tex]
#Using the illustration above, we can express our polar coordinates as:
[tex]-3=\sqrt{x^2+y^2}\\\\-60\textdegree=tan^{-1}(y/x}[/tex]
#Solve simultaneously to solve for x and y:
[tex](-3)^2=x^2+y^2\ \ \ \ \ \ \ \ \ \ i\\\\tan(-0\texdegree)=y/x\ \ \ \ \ \ \ \ ...ii\\\\y=x\ tan(-60\textdegree)\ \ \ \ \ \ \ ...iii\\\\\#substitute\ y \ in\ i\\\\(-3)^2=x^2+(x \ tan (-60\textdegree))^2\\\\9=x^2+3x^2\\\\x=\sqrt{9/4}=1.5\\\\y=1.5\ tan(-60\textdegree)=-2.5981\approx-2.6[/tex]
Hence, the Cartesian coordinates are (1.5,-2.6)
