what is product of the complex numbers 3 - 4i and -6 + i, where i =

Option C:
The product of 3 - 4i and -6 + i is -14 + 27i.
Solution:
Given complex numbers are 3 - 4i and -6 + i.
To find the product of these numbers.
Product of 3 - 4i and -6 + i
[tex]=(3 - 4i)(-6 + i)[/tex]
Multiply each term of first number with each term of second number.
[tex]=3 (-6 + i)-4i(-6+i)[/tex]
[tex]=3 (-6) + 3i -4i (-6)-4i^2[/tex]
Since the value of i² = -1
[tex]=-18+ 3i +24i-4(-1)[/tex]
[tex]=-18+27i+4[/tex]
[tex]=-14+27i[/tex]
The product of 3 - 4i and -6 + i is -14 + 27i.
Option C is the correct answer.
Here we just want to find the product of two complex numbers, we will see that the solution is -14 + 27i
Remember that the complex number i has the property:
i^2 = -1
Now we want to perform the multiplication between 3 - 4i and -6 + i
Then we have:
(3 - 4i)*(-6 + i) = -18 + 3i + (4i)*6 - (4i)*i = -18 + 27i + 4 = -14 + 27i
So the correct option is C.
If you want to learn more about complex numbers, you can read:
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