The value of [tex](\frac{f}{g})(5)[/tex] is [tex]\frac{27}{35}[/tex]
Explanation:
Given that [tex]f(x)=7+4x[/tex] and [tex]g(x)=7x[/tex]
The value of [tex](\frac{f}{g})(5)[/tex]:
The value of [tex](\frac{f}{g})(5)[/tex] can be determined by substituting x = 5 in the functions f(x) and g(x) and then dividing the terms, we get, the value of [tex](\frac{f}{g})(5)[/tex]
Thus, we have,
[tex](\frac{f}{g})(5)=\frac{f(5)}{g(5)}[/tex]
Substituting the value of x = 5 in the functions f(x) and g(x), we get,
[tex](\frac{f}{g})(5)=\frac{7+4(5)}{7(5)}[/tex]
Simplifying the terms, we have,
[tex](\frac{f}{g})(5)=\frac{7+20}{35}[/tex]
Adding the terms in numerator, we have,
[tex](\frac{f}{g})(5)=\frac{27}{35}[/tex]
Thus, the value of [tex](\frac{f}{g})(5)[/tex] is [tex]\frac{27}{35}[/tex]
