Answer:
The coefficient of kinetic friction between the puck and the ice is 0.05.
Explanation:
Given that,
Weight of the hockey puck, W = mg = 3.5 N
Acceleration of the hockey puck, [tex]a=0.45\ m/s^2[/tex]
The frictional force opposing the motion of the puck is given by
[tex]F=\mu N[/tex]
This force is balanced by the force due to motion of the hockey puck. So,
[tex]\mu N=ma\\\\\mu mg=ma\\\\\mu=\dfrac{a}{g}\\\\\mu=\dfrac{0.45}{9.8}\\\\\mu=0.045[/tex]
or
[tex]\mu=0.05[/tex]
So, the coefficient of kinetic friction between the puck and the ice is 0.05. Hence, this is the required solution.
