Answer:
[tex]{(x + 6)}^{2} + {(y - 2)}^{2}=10[/tex]
Step-by-step explanation:
The equation of a circle with center (a,b) and radius r, is
[tex] {(x - a)}^{2} + {(y - b)}^{2} = {r}^{2} [/tex]
From the question, the center of the circle is located at (-6,2) and the radius is
[tex]r = \sqrt{10} [/tex]
We substitute the center and radius to get:
[tex] {(x - - 6)}^{2} + {(y - 2)}^{2} = {( \sqrt{10} })^{2} [/tex]
Simplify to obtain:
[tex]{(x + 6)}^{2} + {(y - 2)}^{2}=10[/tex]
