Answer:
Radius = 3.96m
Explanation:
In a cyclotron motion, the radius of a charged particle path in a magnetic feild is given by:
r = mv/qB
Where r = radius
m = mass of particle= 9.1×10^-31kg
q = charged electron = 1.6×10^-19C
B = magnetic feid = 7.65×10^6T
V = velocity = 7.65×10^6
r = (9.1×10^-31)×(7.65×10^6) / (1.6×10^-19)(1.10 ×10^-5)
r = (6.9615×10^-24)/(1.76 ×10^-24)
r = 3.96m
Answer:
Explanation:
Force of a magnetic field, Fm = q × v × B
Centipetal force, Fa = (M × v^2)/r
Therefore, Fm = Fa
q × v × B = (M × v^2)/r
r = (m × v)/(q × B)
Where,
r = radius
m = mass of electron
= 9.1 × 10^-31 kg
q = electron charge
= 1.602 × 10^-19 C
B = magnetic field
= 1.10 ✕ 10^−5 T
v = velocity
= 7.65×10^6 m/s
r = (9.1 × 10^-31) × (7.65 × 10^6) / (1.6 × 10^-19) × (1.10 × 10^-5)
= 3.95 m
