Respuesta :
The square root of 1000 is between 28 and 32. so option D is correct.
How to find the closest integer less than and greater than the square root of a number?
The function is strictly increasing function for x ≥ 0.
Assuming that all the values of x are ≥ 1, whenever there is increment in the value of 'x', the value of y increases too.
That means, we've got:
[tex]x_1 < x_2 < x_3 \implies \sqrt{x_1} < \sqrt{x_2} < \sqrt{x_3} \: \text{(such that } x_1 \leq 1[/tex]
Perfect square are those integers whose square root is an integer.
Let x-a be the closest perfect square less than x and let x+b be the closest perfect square more than x, then we get: x-a < x < x+b (no perfect square in between x-a and x+b, except possibly x itself).
Then, we get:
[tex]\sqrt{x-a} < \sqrt{x} < \sqrt{x+b}[/tex]
We need to find the square root of 1000
So, the square root of 1000 is 31.6227766017
[tex]\sqrt{1000} = 31.622[/tex]
Thus, The square root of 1000 is between 28 and 32. so option D is correct.
Learn more about square root here:
brainly.com/question/7200235
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