Answer:
44
Step-by-4step explanation:
given that students can enroll in English 1, Math 2, or both for the spring semester.
28 students are enrolled in English 1, 26 are enrolled in Math 2, and 10 are enrolled in both courses.
n(E) = 28, n(M) = 26, n(EM) = 10
where E stands for English and M for Maths
No of students that are enrolled in either English 1 or Math 2
= n(EUM)
= n(E)+n(M)-n(EM)
= [tex]28+26-10\\= 44[/tex]
