The acceleration of a mini marshmallow thrown with a large force is 2.5 m/s2. The acceleration of a potato thrown with the same
force is 1.0 m/s2. What does this imply?
O
O
a
b
the greater the mass, the higher the acceleration
the higher the acceleration, the lower the force
the greater the mass the lower the acceleration
the greater the forces, the higher the acceleation
Od

As per Newton's second law of motion, the acceleration exerted by any object is directly proportional to the unbalanced force acting on that object and inversely proportional to the mass of the object. Mathematically, it is represented as

[tex]a =\frac{F}{m}[/tex]

Now, in the present case, the force is said to applied in same amount for the marshmallow and potato. Let's consider the force applied to marshmallow be represented as F₁ and the force applied to the potato be represented as F₂.

Then the mass of marshmallow be considered as M₁ and the mass of the potato be considered as M₂. Finally, the acceleration of the marshmallow be represented as a₁ and that of potato be represented as a₂.

So, as per the problem, F₁=F₂=F. Then

[tex]a_{1}=\frac{F}{M_{1} }\\ \\a_{2}=\frac{F}{M_{2} }[/tex]

Then, [tex]\frac{a_{1} }{a_{2}} =\frac{m_{2}}{m_{1}}[/tex]

Thus, as there is decrease in the acceleration even though the same amount of force is applied on both, it states that the greater the mass the lower will be the acceleration.

It was proved mathematically above as acceleration is inversely proportional to the mass of the body. So, the greater the mass the lower will be the acceleration.