Answer:
7.35 atm
Explanation:
From the question we are given;
- Initial volume, V1 as 28 L
- Initial temperature, T1 as 42°C or 315 K
- New volume. V2 as 49 L
- New temperature, T2 as 27°C or 300 K
- New Pressure, P2 as 4.0 atm
We are required to determine the initial pressure, P1
We are going to use the combined gas law...
According to the combined gas law,
[tex]\frac{P_{1} V_{1} }{T_1} =\frac{P_2V_2}{T_2}[/tex]
Therefore, to get P1
[tex]P_1=\frac{P_2V_2T_1}{V_1T_2}[/tex]
We get;
[tex]P_1=\frac{(4.0)((49)(315)}{(300)(28)}[/tex]
[tex]P_1=7.35[/tex]
Therefore, the initial pressure of the gas is 7.35 atm
