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A loopful of bacteria containing 1000 bacterial cells is inoculated into a nutrient broth and incubated. After a negligible lag phase, the culture goes into exponential growth for two hours. The generation time for the bacterium is fifteen minutes. Which equation is the correct one to determine the number of cells present after two hours of log phase growth?a. 1000 X 28.
b. 1000 X 16.
c. 1000 X 22.
d. 1000 X 2 X 2 X 15.

Respuesta :

Answer:

a.  1000 X 2^8

Explanation:

As given;

Initial population of bacteria= 1000;

Log phase growth is exponential phase, period in which bacteria gets double.

Generation time= 15 minutes;

it means, bacteria get double in every 15 minute,

so after 2 hours, bacteria will have 8 generation times;

so the final generation of bacteria is =1000 X 2^8.

Final bacterial generation after two hours = 256,000(1000 X 2^8)