Answer:
23.36 T
Explanation:
We are given that
Length of solenoid=l=20 cm=[tex]\frac{20}{100}=0.2 m[/tex]
1 m=100 cm
Number of turns=N=691
Current=I=[tex]5.38kA=5.38\times 10^3 A[/tex]
[tex]1 kA=10^3 A[/tex]
[tex]\mu_0=4\pi\times 10^{-7}Tm/A[/tex]
We have to find the magnetic field inside the solenoid.
We know that the magnetic field of solenoid
[tex]B=\frac{\mu_0NI}{l}[/tex]
Substitute the values
[tex]B=\frac{4\pi\times 10^{-7}\times 691\times 5.38\times 10^3}{0.2}[/tex]
[tex]B=23.36 T[/tex]
