Explanation:
Given data:
G = 11.5×10⁶psi
d₂ = 2.0 inch
d₁ = 1.5 inch
ε[tex]_{max}[/tex] = 170 × 10⁻⁶
Y[tex]_{max}[/tex] = 2ε
T/J = τ[tex]_{max}[/tex] /R
[tex]\frac{Td_{2} }{2J}[/tex] = τ[tex]_{max}[/tex] (1)
τ[tex]_{max}[/tex] = G Y
from 1 and 2
[tex]\frac{T d_{2} }{2J} = G Y_{max}[/tex]
T = [tex]\frac{2 G Y_{max}J }{d_{2} }[/tex]
[tex]\frac{2* 11.5*10^{6}*0.006895*10^{6}*340*10*^{-6} *\frac{\pi }{32}[2^{4}-1.5^{4}]*(0.0254)^{4} }{2* 0.0254}[/tex]
= 474.14 Nm
