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For a pressure of 1.00 atm and a temperature of 24.0 ∘C, use the ideal-gas law to estimate the number of air molecules in the room. Assume all the air is N2. Express your answer to three significant figures and include the appropriate units

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Olajidey

Answer:

mass of air = 324 kg

Explanation:

mass of air = moles of air × molecular weight (N₂)

moles of air = PV / RT

Given that

P = 1 atm

Volume of room = 282 m³

R = 0.082L atm mol⁻¹k⁻¹

                   = (1 × 282 × 10³) / (0.0821 × 297)

                   = 11.565 × 10³mol

molecular weight of N₂ = 28g/mol

mass of air = (11.565 × 10³)mol × 0.028kg/mol

                  = 323.8kg

to three significant figures = 324 kg

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