Answer:
Explanation:
diameter = 4 cm
radius, r = diameter/ 2 = 2 cm
density, d = 0.0845 g/cm³
True weight, W = mg = volume x density x g
[tex]W= \frac{4}{3}\times 3.14\times 2\times 2\times 2\times 0.0845\times 980[/tex]
W = 2773.6 N
Buoyant force acting on the sphere
B = Volume of sphere immersed x density of water x gravity
[tex]B= \frac{4}{3}\times 3.14\times 2\times 2\times 2\times 1\times 980[/tex]
B = 32823.5 N
The amount of force to hold the sphere is
F = Buoyant force - Weight
F = 32823.5 - 2773.6 = 30049.9
F = 30050 N
