Answer:
H₃O⁺(aq) + CO₃²⁻(aq) ⟶ HCO₃⁻(aq) + H₂O(ℓ)
Explanation:
There are three steps you must follow to get the answer.
You must write the:
1. Molecular equation
HNO₃(aq) + Li₂CO₃(aq) ⟶ LiNO₃(aq) + LiHCO₃(aq)
2. Ionic equation
You write the molecular formulas for the weak electrolytes, and you write the ionic substances as ions.
H₃O⁺(aq) + NO₃⁻(aq) + 2Li⁺(aq) + CO₃²⁻(aq) ⟶ Li⁺(aq)(s) + NO₃⁻(aq) + Li⁺(aq) + HCO₃⁻(aq) + H₂O(ℓ)
3. Net ionic equation
To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.
H₃O⁺(aq) + NO₃⁻(aq) + 2Li⁺(aq) + CO₃²⁻(aq) ⟶ Li⁺(aq) + NO₃⁻(aq) + Li⁺(aq) + HCO₃⁻(aq) + H₂O(ℓ)
The net ionic equation is
H₃O⁺(aq) + CO₃²⁻(aq) ⟶ HCO₃⁻(aq) + H₂O(ℓ)