Answer:
The concentration of cyclopropane after 22.0 hour is 0.0457 M.
Explanation:
Conversion of cyclopropane into propene follows first order kinetics.
The integrated rate of first order kinetic is given by :
[tex][A]=[A_o]\times e^{-kt}[/tex]
[tex][A_o][/tex] = Initial concentration of reactant
[tex][A][/tex] = final concentration of reactant after time t
k = rate constant of the reaction
We have :
Rate constant of the reaction = k = [tex]5.4\times 10^{-2} hour^{-1}[/tex]
[tex][A_o]=0.150 M[/tex]
t = 22.0 hour
[A] =?
[tex][A]=0.150 M\times e^{-5.4\times 10^{-2} hour^{-1}\times 22.hour}[/tex]
[tex][A]=0.0457 M[/tex]
The concentration of cyclopropane after 22.0 hour is 0.0457 M.
