This is an incomplete question, here is a complete question.
The change in internal energy for the combustion of 1.0 mol of octane at a pressure of 1.0 atm is -5084.1 kJ. You may want to reference (Pages 381 - 385) Section 9.6 while completing this problem. If the change in enthalpy is -5074.2 kJ, how much work is done during the combustion? Express the work in kilojoules to three significant figures.
Answer : The work done during the combustion is, 9.9 kJ
Explanation :
Formula used :
[tex]\Delta H=\Delta E+w[/tex]
where,
w = work done = ?
[tex]\Delta H[/tex] = change in enthalpy = -5074.2 kJ
[tex]\Delta E[/tex] = change in internal energy = -5084.1 kJ
R = gas constant = 8.314 J/mol.K
Now put all the given values in the above formula, we get:
[tex]-5074.2kJ=-5084.1kJ+w[/tex]
[tex]w=9.9kJ[/tex]
Thus, the work done during the combustion is, 9.9 kJ
