Respuesta :
Answer:
The maximum horizontal range of your gun = 35.378 m
Explanation:
By shooting the dart straight up, we can use the equations of motion to evaluate the initial velocity of the dart as it comes out from the gun
u = initial velocity = ?
v = final velocity at maximum height = 0 m/s
g = - 9.8 m/s
t = time taken to reach maximum height = (total time of flight of the dart)/2 = 3.8/2 = 1.9s
v = u + gt
0 = u - (9.8 × 1.9)
u = 18.62 m/s.
To shoot a projectile to obtain maximum range, the angle of shot, θ = 45°
Range of a projectile is given as
R = [u² sin (2θ)]/g = [18.62² (sin (2 × 45°))]/9.8
R = 35.378 m
The maximum horizontal range of your gun is 35.378 m
Given that,
- u = initial velocity = ?
- v = final velocity at maximum height = 0 m/s
- g = - 9.8 m/s
- t = time taken to reach maximum height = (total time of flight of the dart) ÷ 2 [tex]= 3.8\div 2[/tex] = 1.9s
Calculation of maximum horizontal range of the gun is:
We know that
v = u + gt
0 = u - (9.8 × 1.9)
u = 18.62 m/s.
Now the Range of a projectile is provided as
[tex]R = [u^2 sin (2\theta)]\div g\\\\ = [18.62^2 (sin (2 \times 45^{\circ}))]\div 9.8[/tex]
= 35.378 m
Find out more information about the horizontal range here: https://brainly.com/question/18250643?referrer=searchResults
