Explanation:
Let us assume that the separation of plate be equal to d and the area of plates is [tex]9 \times 10^{-4} m^{2}[/tex]. As the capacitance of capacitor is given as follows.
C = [tex]\frac{\epsilon_{o}A}{d}[/tex]
It is known that the dielectric strength of air is as follows.
E = [tex]3 \times 10^{6} V/m[/tex]
Expression for maximum potential difference is that the capacitor can with stand is as follows.
dV = E × d
And, maximum charge that can be placed on the capacitor is as follows.
Q = CV
= [tex]\frac{\epsilon_{o} A}{d} \times E \times d[/tex]
= [tex]\epsilon_{o}AE[/tex]
= [tex]8.85 \times 10^{-12} \times 3 \times 10^{6} \times 4 \times 10^{-4}[/tex]
= [tex]1.062 \times 10^{-8} C[/tex]
or, = 10.62 nC
Thus, we can conclude that charge on capacitor is 10.62 nC.
