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You flip a fair coin 10,000 times. Approximate the probability thatthe difference between the number of heads and the number of tails is at most 100.

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Imoleowojori

Answer:

E[X] = (np) (p+(1-p))^(n-1)

With n =10,000 and p=0.50 we get

E[X]= (10,000*0.50) (0.50+(1–0.50))^(10,000–1)

E[X] = 5,000(1)

So assuming the coin is fair (p=50%), then we can expect to get heads 5,000 times when the coin is tossed 10,000 times.

Step-by-step explanation:

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