Respuesta :

ibnahmadbello

Answer:

# The user is prompted for input

# the input is assigned to user_tweet

user_tweet = str(input("Enter your tweet here:"))

# if statement to check if LOL is in the user_tweet

if('LOL' in user_tweet):

# If there is LOL in the user_tweet, it display

# LOL means laughing out lous

print("LOL means laughing out loud.")

# if there is no LOL in the user_tweet

# it display "There is no LOL in the tweet

else:

print("There is no LOL in the tweet")

Explanation:

The code is well commented and written in Python.

It prompts the user for tweet, then check if the tweet contains LOL, it there is LOL it displays "LOL means Laughing out loud" else it display "There is no LOL in the tweet".

frknkrtrn

The missing part of the question is:

user_tweet = input()

'''You solution goes here'''

   print('LOL means laughing out loud.')

else:

   print('No abbreviation')

----

We use if-else structure to check if the user_tweet contains 'LOL'.

If the specified condition is true, the if part gets executed. Otherwise, the else part of the program gets executed.

Comments are used to explain each line of the code.

#get the user input

user_tweet = input()

'''

check if the user_tweet contains 'LOL'

if it does, print 'LOL means laughing out loud.'

otherwise, print 'No abbreviation'

'''

if 'LOL' in user_tweet:

   print('LOL means laughing out loud.')

else:

   print('No abbreviation')

You may see a similar question at:

brainly.com/question/24393497

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