Respuesta :
Answer:
The probability a shopper, selected at random, spends less than 96 minutes at the mall is 0.9450
Step-by-step explanation:
Mean = xbar = 88 mins
Standard deviation = σ = 5 mins
To determine the probability the probability a shopper, selected at random, spends less than 96 minutes at the mall, we need to standardize 96 mins, that is, obtain its z-score.
The standardized score is the value minus the mean then divided by the standard deviation.
z = (x - xbar)/σ = (96 - 88)/5 = 1.6
To determine the probability the probability a shopper, selected at random, spends less than 96 minutes at the mall, P(x < 96) = P(z < 1.6)
We'll use data from the normal probability table for these probabilities
P(x < 96) = P(z < 1.6) = 1 - P(z ≥ 1.6) = 1 - P(z ≤ -1.6) = 1 - 0.055 = 0.9450
The probability a shopper, selected at random, spends less than 96 minutes at the mall is 0.9450
