Respuesta :
Answer:
Step-by-step explanation:
[tex]tan~68=\frac{x}{15} \\x=15 tan 68\approx ~37.1~meters.[/tex]
The distance from the object to the point on the ground directly beneath the surveyor is 37.1 meters.
Given that,
- From a point 15 meters above level ground, a surveyor measures the angle of depression of an object on the ground at 68°.
Based on the above information, the calculation is as follows:
[tex]tan 68 = x\div 15\\\\x = 15tan 68[/tex]
= 37.1 meters.
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