From a point 15 meters above level ground, a surveyor measures the angle of depression of an object on the ground at 68°. Approximate the distance from the object to the point on the ground directly beneath the surveyor. (Round your answer to one decimal place.)

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Answer:

Step-by-step explanation:

[tex]tan~68=\frac{x}{15} \\x=15 tan 68\approx ~37.1~meters.[/tex]

The distance from the object to the point on the ground directly beneath the surveyor is 37.1 meters.

Given that,

  • From a point 15 meters above level ground, a surveyor measures the angle of depression of an object on the ground at 68°.

Based on the above information, the calculation is as follows:

[tex]tan 68 = x\div 15\\\\x = 15tan 68[/tex]

= 37.1 meters.

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