Answer:
[tex]\large \boxed{\text{2.42 mol}}[/tex]
Explanation:
We can use the Ideal Gas Law to calculate the number of moles.
pV = nRT
[tex]n = \dfrac{pV}{RT}[/tex]
Data:
p = 1000 kPa = 10.00 bar
V = 6.0 L
R = 0.083 14 bar·L·K⁻¹mol⁻¹
T = 298 K
Calculation:
[tex]n = \dfrac{\text{10.00 bar}\times\text{6.0 L}}{0.08314 \text{ bar}\cdot\text{L}\cdot\text{K}^{-1}\text{mol}^{-1}\times\text{298 K}} = \text{2.42 mol}\\\\\text{You took in $\large \boxed{\textbf{2.42 mol}}$ of oxygen.}[/tex]
