Respuesta :
Answer:
Explanation:
Value of g at a height of 200 km
= GM / (R+h)²
= G is gravitational constant , M is mass of the earth , h is height
= 6.67 x 10⁻¹¹ x 6 x 10²⁴ / [(6380+200)² x 10⁶]
= 9.24 m / s²
Percentage of g
= (9.24 / 9.8 )x100
= 94.28 %
The value of g at 200 km height is 9.24 m[tex]s^{-2}[/tex] and it is 94.28% of the value of g at the surface of the earth.
Let m be the mass of any object at a height of 200 km above earth's surface, R be the radius of earth and M be the mass of earth.
At a height of 200 km, the net force
ma = GMm / (R+h)²
where G is gravitational constant, h is the height = 200 km
a = 6.67 x 10⁻¹¹ x 6 x 10²⁴ / [(6380+200)² x 10⁶]
a = 9.24 m / s²
Comparing to g:
= (9.24 / 9.8 )x100
= 94.28 % of gravitational acceleration on earth's surface.
Learn more about gravitational force:
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