Answer:
The test statistic is -2.5
Yes, I can reject the null hypothesis at 5% significance level.
Step-by-step explanation:
Null hypothesis: The average number of sardines in a can is 9.75
Alternate hypothesis: The average number of sardines in a can is greater than 9.75
Test statistic (z) = (sample mean - population mean) ÷ sd/√n
sample mean = 9.75
population mean = 10
sd = 1
n = 100
z = (9.75 - 10) ÷ 1/√100 = -0.25 ÷ 0.1 = -2.5
The test is a one-tailed test. At 5% significance level, the critical value is 1.645
Conclusion:
Reject the null hypothesis because the test statistic -2.5 is less than the critical value 1.645