Lexan is a plastic used to make compact discs, eyeglass lenses, and bullet-proof glass. One of the compounds used to make Lexan is phosgene (COCl2), an extremely poisonous gas. Phosgene decomposes by the following reaction for which Kp = 6.8 ✕ 10-9 at 100°C. COCl2(g) equilibrium reaction arrow CO(g) + Cl2(g) If pure phosgene at an initial pressure of 2.0 atm decomposes, calculate the equilibrium pressures of all species.

Respuesta :

Answer:

[tex]p_{CO}=1.41atm\\p_{Cl_2}=1.41atm\\p_{COCl2}=0.59atm[/tex]

Explanation:

Hello,

In this case, since the undergoing chemical reaction is:

[tex]Kp=\frac{p_{CO}^{eq}p_{Cl_2}^{eq}}{p_{COCl_2}^{eq}}[/tex]

Thus, if we introduce the changing pressure, [tex]x[/tex], the law of mass action becomes:

[tex]Kp=\frac{(x)(x)}{(2.0atm-x)}[/tex]

Now, by taking the given value of Kp we solve for x as follows:

[tex](2.00atm-x)Kp=x^2\\x^2+Kp*x-2.00atm=0\\x^2+6.8x10^{-9}-2=0\\x_1=1.41atm\\x_2=-1.41atm[/tex]

therefore, the result is 1.41 atm so the equilibrium pressures turn out:

[tex]p_{CO}=1.41atm\\p_{Cl_2}=1.41atm\\p_{COCl2}=2.00-1.41=0.59atm[/tex]

Best regards.