Respuesta :
Answer:
[tex]NO_{2}[/tex]
Explanation:
Given, mass percentage of Nitrogen is 30.44
So, mass percentage of Oxygen is 100 - 30.44 = 69.56
Calculation:-
Element Mass Atomic Number of Simple molar Simple whole
percent mass moles ratio number ratio
Nitrogen 30.44 14 2.17 2.17/2.17 = 1 1
Oxygen 69.56 16 4.34 4.34/2.17 = 2 2
So, Empirical formula = [tex]N_{1}O_{2} = NO_{2}[/tex]
A chemical compound with at least one atom of oxygen is called oxides. The empirical formula of the compound with oxide will be [tex]\rm NO_{2}.[/tex]
What is the empirical formula?
The whole number representation of the atoms present in a compound is called the empirical formula.
The mass percentage is the nitrogen is given as 30.44%. So, the mass percentage of oxygen in the compound will be 100 - 30.44 = 69.56%.
The moles of nitrogen in the compound will be:
[tex]\begin{aligned} \rm moles &= \rm \dfrac{mass}{molar\;mass}\\\\&= \dfrac{30.44}{14}\\\\&= 2.17\;\rm mol\end{aligned}[/tex]
The moles of oxygen in the compound will be:
[tex]\begin{aligned} \rm moles &= \rm \dfrac{mass}{molar\;mass}\\\\&= \dfrac{69.56}{16}\\\\&= 4.34\;\rm mol\end{aligned}[/tex]
The simplest molar ratio of nitrogen will be [tex]\dfrac{2.17}{2.17} = 1[/tex]
The simplest molar ratio of oxygen will be [tex]\dfrac{4.34}{2.17} = 2[/tex]
Therefore, the empirical formula for the oxide-containing compound will be [tex]\rm N_{1}O_{2}[/tex] or [tex]\rm NO_{2}.[/tex]
Learn more about the empirical formula here:
https://brainly.com/question/13396694
