D. The rotation of its spiral path reverses direction.
Explanation:
- Magnetic force on a free moving charge is perpendicular to the velocity of the charge and the magnetic field
F = qvB (eq. 1)
where,
q = charge
v = velocity of the particle
B = strength of the magnetic field
- direction of the force is perpendicular to the motion of the particle
- the particle moves in a circular motion under the action of this magnetic force.
- So the force is equal to the centripetal force
[tex]qvB = m\frac{v^{2}}{r}[/tex]
[tex]r = \frac{mv}{qB}[/tex] (eq. 2)
Where,
m = mass of the particle
r = radius of the orbit
- An ion with initial charge +1 picks up 2 electrons and its charge becomes -1.
- From eq.(1), when the sign of q changes, the direction of the force changes
- So, the ion rotates in the opposite direction
- From eq.(2), the value of q does not change, so the radius of the orbit does not change.
- Therefore, the rotation of its spiral path reverses direction