Answer:
14.139m/s
Explanation:
For a body moving along a curve on a surface whose coefficient of friction is [tex]\mu[/tex], the maximum velocity v the body can sustain beyond which it would skid off is given by equation (1);
[tex]v=\sqrt{\mu gR}............(1)[/tex]
where g is acceleration due to gravity taken as [tex]9.8m/s^2[/tex] and R is the radius of the curve.
Given;
[tex]\mu=0.6\\R=34m[/tex]
Hence'
[tex]v=\sqrt{0.6*9.8*34} \\v=\sqrt{199.92}\\ v=14.139m/s[/tex]
Answer:
Speed = 14.15 m/s.
Explanation:
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