Answer : The concentration of [tex]H^+[/tex] ion is, [tex]1\times 10^{-8}M[/tex]
Explanation : Given,
Concentration of [tex]OH^-[/tex] ion = [tex]1\times 10^{-6}M[/tex]
First we have to calculate the pOH.
[tex]pOH=-\log [OH^-][/tex]
[tex]pOH=-\log (1\times 10^{-6})[/tex]
[tex]pOH=6[/tex]
Now we have to calculate the pH.
[tex]pH+pOH=14\\\\pH=14-pOH\\\\pH=14-6\\\\pH=8[/tex]
First we have to calculate the concentration of [tex]H^+[/tex] ion.
[tex]pH=-\log [H^+][/tex]
[tex]8=-\log [H^+][/tex]
[tex][H^+]=1\times 10^{-8}M[/tex]
Thus, the concentration of [tex]H^+[/tex] ion is, [tex]1\times 10^{-8}M[/tex]
