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When an object is​ dropped, the distance it falls in t​ seconds, assuming that air resistance is​ negligible, is given by ​s(t)equals=4.9054.905t2 where​ s(t) is in meters​ (m). If a stone is dropped from a​ cliff, assuming that air resistance is​ negligible, find the velocity and acceleration of the stone after it had been falling for 1515 sec.

Respuesta :

Olajidey

Answer:

velocity = 147.15 m/s

Acceleration = 9.81 m/s²

Step-by-step explanation:

s(t )= 4.905t²

the  velocity, ds / dt = 2 * 4.905 t

= 9.81 t

if

t = 15 secs

velocity, which is

ds / dt = 9.81 * 15

= 147.15 m/s

Acceleration,

dv / dt = 9.81

After 15 secs, the acceleration is

9.81 m/s²

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