Three tiny charged metal balls are arranged on a straight line. The middle ball is positively charged and the two outside balls are negatively charged. The two outside balls are separated by 20 cm and the middle ball is exactly halfway in between. (HINT: Draw a picture; in your picture, the distance between the two outermost balls should be 20 cm.) The absolute value of the charge on each ball is the same, 1.12 μCoulombs (the meaning of μ, which is read as "micro", is 10-6). Give your answers in newtons.
(a) What is the magnitude of the attractive force on either outside ball due ONLY to the positively-charged middle ball? N
(b) What is the magnitude of the repulsive force on either outside ball due ONLY to the other outside ball? N
(c) What is the magnitude of the net force on either outside ball? N

As per the question the tiny metal ball is arranged on a straight line and the central ball is positively charged and has two sides that are negatively charged. The outside ball is separated by 20 cm in middle is halfway in between.

Thus the answer to the magnitude is 14.29 N, the magnitude of the repulsive force is 0.35N and the net force is 0 North.

The metal ball is a at a distance of 20 cm an has an absolute value of change that is on each ball and is same as 1.12u.

The force of attraction has a magnitude of 14.2 due to the positively changed middle balls. The repulsive forced of either side of the ball are 0.35 north and net is 0 outside the ball.

Hence the change of the ball determines the direction.

Find out more information about the metal ball.

brainly.com/question/26368502.