Respuesta :
Answer:
The % yield of AgCl is 81.1 %
Explanation:
Step 1: Data given
Mass of AgNO3 = 5.95 grams
Molar mass AgNO3 = 169.87 g/mol
Molar mass BaCl2 = 208.23 g/mol
Mass of AgCl = 4.07 grams
Molar mass of AgCl = 143.32 g/mol
Step 2: The balanced equation
2AgNO3 + BaCl2 → 2AgCl + Ba(NO3)2
Step 3: Calculate moles AgNO3
Moles AgNO3 = mass AgNO3 / molar mass AgNO3
Moles AgNO3 = 5.95 grams / 169.87 g/mol
Moles AgNO3 = 0.0350 moles
Step 4: Calculate moles AgCl
For 2 moles AgNO3 we need 1 mol BaCl2 to produce 2 moles AgCl and 1 mol Ba(NO3)2
For 0.0350 moles AgNO3 we'll have 0.0350 moles AgCl
Step 5: Calculate mass AgCl
Mass AgCl = moles AgCl * moles AgCl
Mass AgCl = 0.0350 moles * 143.32 g/mol
Mass AgCl = 5.016 grams
Step 6: Calculate % yield AgCl
% AgCl = (4.07 grams / 5.016 grams)*100 %
% AgCl = 81.1 %
The % yield of AgCl is 81.1 %
The percentage yield of AgCl is 81.1%
The balanced equation for the reaction is given below:
2AgNO₃ + BaCl₂ —> 2AgCl + Ba(NO₃)₂
Next, we shall determine the mass of AgNO₃ that reacted and the mass of AgCl produced from the balanced equation.
Molar mass of AgNO₃ = 108 + 14 + (3×16)
= 108 + 14 + 48
= 170 g/mol
Mass of AgNO₃ from the balanced equation = 2 × 170 = 340 g
Molar mass of AgCl = 108 + 35.5
= 143.5 g/mol
Mass of AgCl from the balanced equation = 2 × 143.5 = 287 g
Thus,
From the balanced equation above,
340 g of AgNO₃ reacted to produce 287 g of AgCl.
Next, we shall determine the theoretical yield of AgCl obtained by the reaction of 5.95 g of AgNO₃
This can be obtained as follow:
From the balanced equation above,
340 g of AgNO₃ reacted to produce 287 g of AgCl.
Therefore,
5.95 g of AgNO₃ will react to produce = [tex]\frac{5.95 * 287 }{340}[/tex] = 5.02 g of AgCl.
Thus, the theoretical yield of AgCl is 5.02 g
Finally, we shall determine the percentage yield of AgCl. This is illustrated below:
Actual yield AgCl = 4.07 g
Theoretical yield of AgCl = 5.02 g
Percentage yield of AgCl =?
[tex]Percentage yield = \frac{Actual}{Theoretical} * 100\\\\Percentage yield = \frac{4.07}{5.02} * 100[/tex]
Percentage yield of AgCl = 81.1%
Therefore, the percentage yield of AgCl is 81.1%
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