Respuesta :

Soban

i = 11

while i < 36:

   print(i)

   i = i + 1

Hope it helps.

The idea is the following (the specific code will vary depending on the specific language):

  • declare a global counter, i = 11, and an inner counter, c = 0.
  • make a for loop where i runts from 11 to 35 (inclusive)
  • for each iteration, print i and increase c by 1. If c=5, print a return carriage (\n) and reset count to 0.

For example, in Java you'd have

public class PrintNumbers{

    public static void main(String []args){

       int i;

       int c = 0;

       for (i=11; i<=35; i++){

           System.out.print(i + " ");

           c++;

           if(c==5){System.out.print("\n"); c=0;}

       }

    }

}

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