Respuesta :

Answer:

6.25 g of radon-222 is left over after 15.2 days

Explanation:

You must start by finding out how many half lives have occurred over the time. This can be done by dividing the time passed by the half-life.

15.2/3.8=4

Now that the amount of half-lives is known now you must take that amount away from the original sample.

100/2=50

50/2=25

25/2=12.5

12.5/2=6.25

onyebuchinnaji

The mass of the radon sample remaining after 15.2 days is 6.25 g.

The given parameters:

  • half life of the radon, [tex]t_{1/2}[/tex] = 3.8 days
  • initial mass of the radon sample, m = 100 g
  • time of decay, t = 15.2 days

The number of times the radon sample decayed is calculated as follows;

[tex]n = \frac{15.2}{3.8} \\\\n = 4[/tex]

The mass of the radon sample remaining after 4 series of decay is calculated as follows:

[tex]m = \frac{m_0}{2^n} \\\\m = \frac{100}{2^4} \\\\m = 6.25 \ g[/tex]

Thus, the mass of the radon sample remaining after 15.2 days is 6.25 g.

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