You have not provided the coordinates for the original object i.e. the square PQRS, therefore, I am taking the sample vertices of the square PQRS to provide an exact answer, which anyways would help you in terms of clearing your concept.
The sample coordinates of the square PQRS are: P(1, -1), Q(1, 2), R(-2, 2). and S(-2, -1)
Answer:
When the square PQRS withe vertices P(1, -1), Q(1, 2), R(-2, 2). and S(-2, -1) is rotated 90° clockwise using the origin as the center of rotation, the vertices of the image P’Q’R’S’ will be:
Step-by-step explanation:
The rule for an object rotated 90° clockwise using the origin as the center of rotation
"When the point , let say A (x, y) is rotated through [tex]90^{0}[/tex] clockwise about the origin, the point A (x, y) takes the image A' (y, -x)."
For example, let suppose there is a square PQRS with the vertices as:
As we know that When the point , let say A (x, y) is rotated through [tex]90^{0}[/tex] clockwise about the origin, the point A (x, y) takes the image A' (y, -x).
So,
When the square PQRS is rotated 90° clockwise using the origin as the center of rotation, the vertices of the image P’Q’R’S’ will be:
