Answer:
Original side of the square =5 inches
Step-by-step explanation:
The side of the square is increasing by 3
Let the original side of the square be 'a' inches.
GIVEN:
On increasing side by 3 side becomes=a+3 inches
On increasing the side the area becomes 64 square inches
Area of a square= [tex]side*side[/tex]
[tex]64= (a+3)(a+3)\\64=a^2+3a+3a+9\\64=a^2+6a+9\\a^2+6a=64-9\\a^2+6a=55\\a^2+6a-55=0\\a^2-5a+11a-55=0\\a(a-5)+11(a-5)=0\\(a-5)(a+11)=0\\a=5 \\or\\a=-11[/tex]
As the side cannot be negative, so the original side of the square is 5 inches
