Respuesta :
Answer:
Energy stored = 695.8joules
Explanation:
Energy stored in a capacitor = C * v²/2
Where c = capacitance = 31ụf
V = voltage = 6.70 *10^3
So therefore:
Energy = (31 * 10^-6) * ( 6.70 * 10^3)²/2
= 695.8 joules
Answer: Note that voltage of the defibrillator is given as 6.70*103V instead of 6.70*10^3volts
The answer is:
Ecap=6957950joules
Explanation:
Ecap=CV^2/2
Where Ecap( Energy in joules) =?
V(Voltage in volt)=6.70*10^3volts
C(capacitance )=31.0µF =31*10^-6F
Ecap=(31*10^-6F)*(6.70*10^3volts)^2/2=13915900/2
Ecap=6957950joules
