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What is the equation of the line that passes through (4, -1) and (-2, 3)?
2 x + 3 y - 5 = 0
-2 x + 3 y - 5 = 0
2 x - 3 y - 5 = 0

Respuesta :

Yang100

Answer:

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(3-(-1))/(-2-4)

m=(3+1)/-6

m=4/-6

simplify

m=-2/3

y-y1=m(x-x1)

y-(-1)=-2/3(x-4)

y+1=-2/3(x-4)

y+1=-2/3x+8/3

y=-2/3x+8/3-1

y=-2/3x+8/3-3/3

y=-2/3x+5/3

y-(-2/3x)=5/3

y+2/3x=5/3

2/3x+y=5/3

3(2/3x+y)=3(5/3)

2x+3y=5

2x+3y-5=0

Iilyevans

Answer:

hii!

2x+3y-5=0 is ur answer, just did the test!

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