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20-02-2020
Engineering

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The current in a 67-Ω resistor is 0.12 A. This resistor is in series with a 35-Ω resistor, and the series combination is connected across a battery. What is the battery voltage?

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barnabasokoduwa11 barnabasokoduwa11

20-02-2020

Answer:

Explanation:

Resistor in series= R1+R2

Thus- 57+35= 92ohms

Voltage- IR

0.12×92= 11.04V

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