Respuesta :
Answer:
Step-by-step explanation:
1.
"D. For a random sample of 50 customer wait times, the probability that the sample mean customer wait time will be greater than 25 minutes is approximately 0.10" is correct.
2.
"B. The mean of the sampling distribution of the sample mean is 150 hot dogs" is correct.
(since the mean of all sample means is equal to the population mean which is 150, here).
3.
"B. 2.7−4.2=−1.5" is correct.
(Option D. is incorrect because we want μ(x¯1−x¯2) but not μ(x¯2−x¯1); Option A. is incorrect because 3 and 7 are sample sizes and we are not interested in the difference between sample sizes. Option C. is incorrect because there are no such values as 2.73 and 4.27, here).
4.
"C. No, the conditions for normality have not been met because the sample size for the pennies is not large enough and no information is given about the distributions of the populations" is correct.
(since 25 pennies < 30 is considered small sample and 35 quarters > 30 is considered large sample).
Answer:
1) D
2) D
3) B
4) A
Step-by-step explanation:
1) D, P(50 > 25) ≈ 0.10 ⇒ the random sample of 50 customer wait times, the probability that the sample mean customer wait time will be greater than 25 minutes is approximately 0.10
2) D, (150 - 140) hot dogs = 10 hot dogs
3) B, 2.7- 4.7 = -1.5
4) A, (i) 25 + 25/4 = 25 + 6.25 = 31.25 ≈ 32 years
(ii) 35 + 35/4 = 35 + 8.75 = 43.75 ≈ 44 years