Respuesta :
The question is incomplete! Complete question along with answers and explanation is provided below.
Question:
A student randomly selects one marble from the group of marbles shown below and then tosses a balanced coin.
3 red marbles
4 green marbles
2 blue marbles
A. What is the probability that the student will select a green marble and then toss a heads? Show all your work.
B. Use your answer in A to determine the likelihood that the student will select a green marble and then toss a heads. Explain your reasoning in complete sentences.
Answer:
P(green and heads) = 2/9 = 0.22
Step-by-step explanation:
A.) What is the probability that the student will select a green marble and then toss a heads? Show all your work.
Probability of selecting a green marble = no. of green marbles/total no. of marbles
no. of green marbles = 4
total no. of marbles = 3 + 4 +2 = 9
P(green) = 4/9
Probability of tossing heads = no. of interest outcomes/total no. of outcomes
no. of interest outcomes = 1 (heads)
total no. of outcomes = 2 (heads, tails)
P(heads) = 1/2
P(green and heads) = P(green)*P(heads)
P(green and heads) = 4/9*1/2
P(green and heads) = 2/9 = 0.22
B. Use your answer in A to determine the likelihood that the student will select a green marble and then toss a heads. Explain your reasoning in complete sentences.
In this problem we want to know the probability of 2 different events happening at the same time or one after another which are not depended on each other.
Whether you are selecting a green marble or a red one this will not going to effect the probability of getting a head or tail. In such a case, we multiply the probabilities of these 2 events to get the combined probability.
Answer:
For A: I know the coin is 50% but if you count the marbles you can put that as the denominator and the numerator as the green marbles I guess and find the percent
