Answer:
The amount invested at 5% was $39,000 and the amount invested at 7% was $11,000
Step-by-step explanation:
we know that
The simple interest formula is equal to
[tex]I=P(rt)[/tex]
where
I is the Final Interest Value
P is the Principal amount of money to be invested
r is the rate of interest
t is Number of Time Periods
Let
x-----> the amount invested at 5%
50,000-x -----> the amount invested at 7%
so
[tex]t=1\ year\\ I=\$2,720\\r_1=0.05\\r_2=0.07\\P_1=\$x\\P_2=\$(50,000-x)[/tex]
substitute in the formula above
[tex]2,720=x(0.05*1)+(50,000-x)(0.07*1)[/tex]
solve for x
[tex]2,720=0.05x+3,500-0.07x[/tex]
[tex]0.07x-0.05x=3,500-2,720\\0.02x=780\\x=\$39,000[/tex]
[tex](50,000-x)=\$11,000[/tex]
therefore
The amount invested at 5% was $39,000 and the amount invested at 7% was $11,000