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Find a polynomial (with real coefficients) of degree 4 with zeros at -3 (multiplicity of 2) and -2i, and with 6 as the coefficient of x

Respuesta :

Answer:

Step-by-step explanation:

If -2i is a root, then so is +2i, so

y = a(x+3)^2(x^2+4)

= a(x^4+6x^3+13x^2+24x+36)

Since we want 24a = 6, our final polynomial is

y = 1/4 (x^4+6x^3+13x^2+24x+36)

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