Respuesta :
Answer:
[tex]5.2\times 10^5N/C[/tex]
Explanation:
Since the two charged bodies are symmetric, we can calculate the electric field taking both of them as point charges.
This can be easily seen if we use Gauss's law, [tex]\int{E} \, dA=\frac{Q_{enclosed}}{\epsilon_o}[/tex]
We take a larger sphere of radius, say r, as the Gaussian surface. Then the electric field due to the charged sphere at a distance r from it's center is given by,
[tex]E=\frac{1}{4\pi r^2} \frac{Q_{enclosed}}{\epsilon_o}[/tex]
which is the same as that of a point charge.
In our problem the charges being of opposite signs, the electric field will add up. Therefore,
[tex]E_{total}=\frac{1}{4\pi\epsilon_o}\frac{q_1+q_2}{r^2}= (9\times10^9) \frac{(76+30)\times10^{-9}}{((1+3.3)\times10^{-2})^2}N/C =5.2\times10^5N/C[/tex]
where, [tex]r[/tex] = distance between the center of one sphere to the midpoint (between the 2 spheres)
